Latex 数学公式可用性测试
∂r∂ωr(yωω)=(yωω){(logy)r+∑i=1r(−1)ir⋯(r−i+1)(logy)r−iωi} \frac {\partial^r} {\partial \omega^r} \left(\frac {y^{\omega}} {\omega}\right) = \left(\frac {y^{\omega}} {\omega}\right) \left\{(\log y)^r + \sum_{i=1}^r \frac {(-1)^i r \cdots (r-i+1) (\log y)^{r-i}} {\omega^i} \right\} ∂ωr∂r(ωyω)=(ωyω){(logy)r+i=1∑rωi(−1)ir⋯(r−i+1)(logy)r−i}
